Question

hi plz explain this !!!! plz i need detailed answer..

answer is in my first question.
just explain me tht step​

Answer 1

ANSWER

No. of moles in 50 ml of  1 M oxalic acid is = 100050L×1M=0.05 moles of oxalic acid.

After adsorption, remaining moles of oxalic acid=100050L×0.5M=0.025 moles.

Thus, moles that adsorb on charcoal is =0.05−0.025=0.025 moles of oxalic acid.

Therefore, 0.025 moles of oxalic acid adsorb on 0.5 g of charcoal.

1 gram of charcoal moles adsorb=0.50.025=0.05 moles of oxalic acid.

Amount of oxalic acid adsorbed per gram of charcoal = 0.05×126g/mole=6.30grams

Thus, 6.30 g of oxalic acid adsorb per gram of charcoal. 

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Answer 2

Answer:

hey...

C is right...

ok