Math, asked by GREEDLING, 10 months ago

hi plz help me in this question ​

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Answered by Ashutoshkumar7432
1

Answer:

Given (a+b+c) [(a-b)^2 + (b-c)^2 + (c-a)^2]

= (a+b+c)(a^2 + b^2-2ab + b^2 + c^2-2bc + c^2 + a^2- 2ac)

= (a+b+c)[2(a^2 + b^2 + c^2) -2(ab+bc+ca)]

= 2(a+b+c)(a^2 + b^2 + c^2 - ab - bc - ca)

= 2{a^3 + b^3 + c^3 - abc - abc- abc}

Remaining all terms will get cancelled

= 2(a^3 + b^3 + c^3 - 3abc)

Answered by shakira0410
0
Solution of your problem
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