Question

Hi plz solve this question is urgently..

Answer 1

$Given : \frac{d}{dx} ( \frac{x^2 - 1}{x^2 + 1} )$

$= \ \textgreater \ \frac{ \frac{d}{dx}(x^2 - 1) * (x^2 + 1) - (x^2 - 1)* \frac{d}{dx}(x^2 + 1) }{(x^2 + 1)^2}$

$= \ \textgreater \ \frac{ (\frac{d}{dx}(x^2) + \frac{d}{dx} (-1)) (x^2 + 1) - ( \frac{d}{dx} (x^2 + \frac{d}{dx}(1))(x^2 - 1) }{(x^2 + 1)^2}$

$= \ \textgreater \ \frac{(2x + 0)(x^2 + 1) - (2x + 0)(x^2 - 1)}{(x^2 + 1)^2}$

$= \ \textgreater \ \frac{2x(x^2 + 1) - 2x(x^2 - 1)}{(x^2 + 1)^2}$

$= \ \textgreater \ \frac{2x^3 + 2x - 2x^3 + 2x}{(x^2 + 1)^2}$

$= \ \textgreater \ \frac{4x}{(x^2 + 1)^2}$


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks