Question

hi
Q. factorise these​

Answer 1

Answer:

$a) \frac{2 {a}^{2} + 11a + 12}{2a + 3} \\ = \frac{2 {a}^{2} + 8a + 3a + 12 }{2a + 3} \\ = \frac{(2 {a}^{2} + 8a) + (3a + 12)}{2a + 3} \\ = \frac{2a(a + 4) + 3(a + 4)}{2a + 3} \\ = \frac{(2a + 3)(a + 4)}{2a + 3} \\ = a + 4 \\ b) \frac{81 {a}^{2} - 64 {b}^{2} }{9a - 8b} \\ = \frac{ {(9a)}^{2} - {(8b)}^{2} }{9a - 8b} \\ = \frac{(9a + 8b)(9a - 8b)}{9a - 8b} \\ = 9a + 8b$