Question

Hi,

Question:-
How many times will the incident beam shown in fig. be reflected by each of the parallel mirrors?
(tan(14°) = 0.25)

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Answer 1

Question:

How many times will the incident beam shown in fig. be reflected by each of the parallel mirrors?

tan(14°) = 0.25.

Solution:

At the left hand mirror at distance this incident light reaches.

→ d2 = (1m) tan14° = 0.25 m

Now let's , find the height of light reaching the right hand mirror.

→ d = 1 × (0.25 m)

After multiplying (1 × 0.25 m) we get the same "0.5" .

→ d = 0.25 m

Length of reflections = 1 m.

Let's , find Total number of reflections from right hand.

→ ᴺ right = 1m / 0.25

→ 4

Therefore, 4 times the incident beam shown in given figure.

Answer 2

Answer:

Refer to the given attachment

Explanation:

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