Question

Hi....

Sin30° + tan 45°- cosec60°
cot45°+cos60°-Sec30°

Answer 1

$\frac{ \sin(30) + \tan(45) - \cosec(60) }{ \cos(60) + \cot(45) - \sec(30) } \\ \\ \\ \\ => \frac{ \sin(90 - 60) + \cot(90 - 45) - \cosec(90 - 30) }{ \cos(60) + \cot(45) - \sec(30) } \\ \\ \\ \\ => \frac{ \cos(60) + \cot(45) - \sec(30) }{ \cos(60) + \cot(45) - \sec(30) } \\ \\ \\ as \: both \: are \: same \: \\ \\ \\ => 1$

Answer 2

Hello Friend....

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The answer of u r question is....

Ans:

=1/2+ 1 - 2/√3
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1 + 1/2 -2/√3..


=√3 + 2√3 - 4
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2√3
_____________
2√3 + √3-4
-----------------
2√3

=3√3-4
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2√3
_________
3√3-4
----------
2√3

both gets cancel..

= 1

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Thank you...⭐️⭐️⭐️⭐️