Hi! solve guys❤Quēstion here ;
If m times the m^th term of an A.P. is equal to n times its n^th term,show that the(m+n)^th is zero(0) ⠀⠀⠀⠀
⠀Kindly solve fully :)
Answers
Step-by-step explanation:
Given:
mth times mth term of AP = n times the nth term.
⇒ m * [a + (m - 1) * d] = n * [a + (n - 1) * d]
⇒ m * [a + (m - 1) * d] - n * [a + (n - 1) * d] = 0
⇒ ma + m(m - 1) * d - na - n(n - 1) * d = 0
⇒ ma + (m² - m) * d - na - (n² - n) * d = 0
⇒ a(m - n) + [d(m² - n²) - d(m - n)] = 0
⇒ a(m - n) + d[(m + n)(m - n) - (m - n)] = 0
⇒ (m - n)[a + d((m + n) - 1)] = 0
⇒ a + [(m + n) - 1]d = 0
Therefore,
It denotes (m + n)th term is 0.
Hope it helps!
▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬
▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬
M'th term
N'th term
To prove :
a + (m+n-1)d = 0
According to question
m(M'th term) = n(N'th term)
m(a + (m-1)d) = n(a + (n-1)d)
m(a+md-d) = n(a+nd-d)
ma + m²d - md = na + n²d - nd
ma - na + m²d - n²d - md + nd = 0
a(m-n) + d(m²-n²) - d(m-n) = 0
Dividing (m-n) on bhs
a + d(m+n) - d = 0
a + d(m+n-1) = 0
(m+n)th term = 0
Hence proved ✔✔
.
Ab mai itna b khaas ni :shy ❤