Question

hi solve the following​

Answer 1

since

$log(x \times y) = log(x) + log(y)$

log(x-2)+log(x+2)=log5

log(x-2)(x+2)=log5

(x-2)(x+2)=5

$x {}^{2} - 2 {}^{2} = 5 \\ x {}^{2} - 4 = x {}^{2} = 9 \\ x = 3$