hi solve this plzzzzzzzzzzzzzzzzzzz
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Let t1 & t2 be time taken to reach the ground then from the formula,
h= 1/2 gt^2,
For first body, 16 =1/2 gt(1 )²
For second body, 25 =1/2 gt2²
16/25 =(t1^( 2))/(t2^( 2) ) ? t1/t2 = 4/5.
h= 1/2 gt^2,
For first body, 16 =1/2 gt(1 )²
For second body, 25 =1/2 gt2²
16/25 =(t1^( 2))/(t2^( 2) ) ? t1/t2 = 4/5.
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