Hi
solve this question
Attachments:
Answers
Answered by
0
Given
QR/QS= QT/PR. - (1)
angle 1 = angle 2 - (2)
Let start,
From Eq 2
angle 1 = angle 2
so, PR = PQ. -(3)
ALSO,
FROM EQ 1
QR/QS = QT/PR
from eq 3
QR/QS = QT/PQ
In ∆PQS and ∆TQR
(S) QR/QS = QT/PQ
(A) angle 1 = angle 2
Therefore, ∆PQS ~ ∆TQR
HOPE IT HELP YOU
Please mark it brainlist if you happy...
QR/QS= QT/PR. - (1)
angle 1 = angle 2 - (2)
Let start,
From Eq 2
angle 1 = angle 2
so, PR = PQ. -(3)
ALSO,
FROM EQ 1
QR/QS = QT/PR
from eq 3
QR/QS = QT/PQ
In ∆PQS and ∆TQR
(S) QR/QS = QT/PQ
(A) angle 1 = angle 2
Therefore, ∆PQS ~ ∆TQR
HOPE IT HELP YOU
Please mark it brainlist if you happy...
Similar questions