Math, asked by sowmiya35, 1 year ago

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Answered by peedhsrah
0
Given
QR/QS= QT/PR. - (1)
angle 1 = angle 2 - (2)

Let start,

From Eq 2
angle 1 = angle 2
so, PR = PQ. -(3)
ALSO,
FROM EQ 1
QR/QS = QT/PR
from eq 3
QR/QS = QT/PQ

In ∆PQS and ∆TQR
(S) QR/QS = QT/PQ
(A) angle 1 = angle 2

Therefore, ∆PQS ~ ∆TQR

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