Question

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solve this question step by step​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf H=10mm\:of\:Hg}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Density of air ($\sf{\rho_{air}) =1.295 kgm^{-3}}$

• Height above he sea level (h)=107m

• Density of mercury ($\sf{\rho_{mercury} =13.6×10^3kgm^{-3}}$

$\large\underline\pink{\sf To\:Find: }$

• Fall in barometric height (H) = ?

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$\large{♡}$${\boxed{\sf Decrease\:in\: Pressure\:of\:air=\rho gh }}$

$\large\implies{\sf 1.295×g×107\:Pa }$

$\large\implies{\sf 138.565g\:Pa}$

$\large{♡}$${\boxed{\sf Decrease\:in\: Pressure\:of\: mercury=\rho gH }}$

Here ,

H = Decrease in barometric height

$\large\implies{\sf 13.6×10^3×g×H}$

$\large{♡}$$\large{\boxed{\sf H=\frac{\rho_{air} gh}{\rho_{mercury} g}}}$

On Putting value :

$\large\implies{\sf H= \frac{138.565}{13.6×10^3}}$

$\large\implies{\sf H=10mm\:of\:Hg}$

$\huge\red{♡}$$\large\red{\boxed{\sf H=10mm\:of\:Hg}}$

Decrease in barometer height is 10mm of Hg

Answer 2

Answer:

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