Question

hi
${3x}^{4 } - {13x}^{2} + 10 = 0$

Answer 1

Answer:

x = +/- 1. &

x = +/-(root(10/3))

Step-by-step explanation:

3x^4 -13x^2 + 10 = 0

=> 3x^4 - 3x^2 -10x^2 + 10 = 0

=> 3x^2(x^2 -1) -10(x^2-1) = 0

=> (3x^2-10)(x^2-1)=0

=> x = +/- 1. &

x = +/-(root(10/3))

Answer 2

here is ur answer----------------❤❤❤

Factoring 3x4-13x2-10

The first term is, 3x4 its coefficient is 3 .

The middle term is, -13x2 its coefficient is -13 .

The last term, "the constant", is -10

Step-1 : Multiply the coefficient of the first term by the constant 3 • -10 = -30

Step-2 : Find two factors of -30 whose sum equals the coefficient of the middle term, which is -13 .

-30 + 1 = -29

-15 + 2 = -13 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 2

3x4 - 15x2 + 2x2 - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

3x2 • (x2-5)

Add up the last 2 terms, pulling out common factors :

2 • (x2-5)

Step-5 : Add up the four terms of step 4 :

(3x2+2) • (x2-5)

hope it helps u dear.......❤❤❤❤