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explain and derive law of conservation of energy....
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✔️✔️ ANSWER ✔️✔️
✔️✔️LAW OF CONSERVATION OF ENERGY ✔️✔️
energy can neither be created nor be destroyed. It may be transferred from one of its forms to the other
✔️DERIVATION ✔️
Consider a point A, which is at some height ‘H’ from the ground on the tree, the velocity of the fruit is zero hence potential energy is maximum there.
E = mgH ———- (1)
When the fruit is falling, its potential energy is decreasing and kinetic energy is increasing
At point B, which is near the bottom of the tree, the fruit is falling freely under gravity and is at a height X from the ground, and it has a speed as it reaches point B. So, at this point it will have both kinetic and potential energy.
E = K.E + P.E
P.E = mgX ——— (2)
According to third equation of motion,
v2=2g(H–X)⇒12mv2=12m.2g(H–X)⇒K.E=12m.2g(H–X)⇒K.E=mg(H–X)
K.E=mg(H-X)——– (3)
Using (1), (2) and (3)
E = mg(H – X) + mgX
E = mg(H – X + X)
E = mgH
✔️✔️Suppose we need to find that height ‘x’ from the ground. We know that at that point,
K.E = P.E
=> P.E = K.E = E2 ——– (4)
E2 is the new energy
Where, E = mgH2
H2 is the new height.
As the body is at height X from the ground,
P.E = mgX ——— (5)
Using (4) and (5) we get,
mgX=mgH2⇒X=H
I HOPE THIS INFO HELPS YOU ☺️☺️
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