hi
The co-ordinates of end points of a diameter of a circle are (7,9) and (-1, -3). The
co-ordinates of centre of circle is
(a) (3,3) (b) (4,6) (C) (3,-3) (d) (4, -6)
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Answer:
Let the diameter pf circle be AB and O be the centre of the circle and A(7,9) and B(-1,-3) be the given coordinates of the diameter.
Now,
AO = BO (since AO and BO are radous of circle)
By midpoint formula we get-
Coordinates of O
= {(x1+x2/2),(y1+y2)}
= {(7+(-1)/2),9+(-3)/2}
= {(7-1/2),(9-3/2)}
= {(6/2),(6/2)
= (3,3)
THEREFORE OPTION A IS CORRECT.
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