Hi.....
The difference of two square nos. is 180 and the square of the smaller no. is 8 times the larger no. Find the two nos.
!!50 pts!!
Thanks!
Answers
Answered by
6
Final Answer : Larger Number = 18
Smaller Number = ±12
Let the smaller number be 'y'and larger number be 'x'.
According to the question, we know
Using eq. (1) and (2),
We get
Since, x can't be negative as y^2 is always positive so 8x has to be positive.
=> x is positive.
x = -10 is rejected.
Now, substitute value of x = 18 in equation (2),
we get
y^2 = 8*18
=> y^2 = 144
=> y = ±12
Therefore, Larger number = 18
Smaller Number = 12 or -12
Smaller Number = ±12
Let the smaller number be 'y'and larger number be 'x'.
According to the question, we know
Using eq. (1) and (2),
We get
Since, x can't be negative as y^2 is always positive so 8x has to be positive.
=> x is positive.
x = -10 is rejected.
Now, substitute value of x = 18 in equation (2),
we get
y^2 = 8*18
=> y^2 = 144
=> y = ±12
Therefore, Larger number = 18
Smaller Number = 12 or -12
Answered by
0
Answer:
!!
Step-by-step explanation:
Let the larger number = x
Then the square of the smaller number = 8 times the larger number = 8x
and the square of the larger number = x2
According to the question,
x2 - 8x = 180
=> x2 - 8x - 180 = 0
=> x2 - 18x + 10x - 180 = 0
=> x(x - 18) + 10(x - 18) = 0
=> (x - 18) (x + 10) = 0
=> x - 18 = 0 or x + 10 = 0
=> x = 18 or x = -10
Thus, the larger number = 18 or -10
Then, the square of the smaller number = 8(18) or 8(-10)
= 144 or -80
The square of a number can't be negative, so, the square of smaller number = 144
Hence, the smaller number = sqrt(144) = 12
The numbers are 12 and 18
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