Question

hi !


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The positive number is 5 times another number if 21 is added to both the number then one of the new number becomes twice the other number find the two number.



Answer it.


Thanks !

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Answer 1

Hey mate!!

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Let x be the first number and let y be the second number. From the first statement, we have:

x = 5y.

From the second statement, we have:

x + 21 = 2 × (y + 21).

[Since x = 5y, x must be greater than y, so x + 21 must be greater than y+ 21. That's how we know x + 21 = 2 × (y + 21), rather than the other way around, y + 21 = 2 × (x + 21).]

So all we have to do is solve this system of equations. This can be done easily by substitution, since the first equation is already solved for x. Plugging in 5y for x in the second equation, we have:

5y + 21 = 2 × (y + 21)

5y + 21 = 2y + 42

3y + 21 = 42

3y = 21                       

y = 7                            

Thus, y = 7

And x = 5y = 5 × 7 = 35,

so the two numbers are 7 and 35. 

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Thanks for the question!!

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Answer 2

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Hey

Here is your answer,

let one of the number be x.

second number be 5x.

2(x+21)=(5x+21)

=> 2x+42=5x+21

=> 2x−5x=21−42

=> −3x=−21

x=7

One of the number 7

Second number 7×5=35

Answer : 7,35

Hope it helps you!