Question

Hi the question is write the discriminant of the quadratic equation px^2+qx-r=0

Answer 1

Answer:

d=b^2-4ac

D=q^2-4*p*-r

D=q^2+4pr..............ans

Step-by-step explanation:

Answer 2

Answer:

$x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$

Step-by-step explanation:

We are given an equation : $px^2+qx-r=0$

General form of quadratic equation :$ax^{2}+bx+c=0$

On comparing with general form

a = p

b = q

c = -r

Formula of discriminant : $x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute the values in the formula .  

$x = \frac{-q\pm\sqrt{q^2-4p(-r)}}{2p}$

$x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$

Thus the discriminant of    $px^2+qx-r=0$  is   $x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$