Question

Hi




The sum of 3 consecutive numbers is 90...
Find number..



# point distribution...

Answer 1

$\huge{\boxed{\huge{\red\star\mathfrak\purple{\large{\underline{\underline{ Answer!}}}}}}}$

Let the unknown number be x

1st number= x

2nd number= (x+1)

3rd number= (x+2)

Now, according to the question

x+(x+1)(x+2)= 90

3x+3= 90

3x= 90+3

3x= 93

$\huge \boxed { \mathfrak\red{x = \frac{93}{3}}}$

x= 31

1st number= x= 31

2nd number= x+1= 31+1= 32

3rd number= x+2= 31+2= 33

Answer 2

Answer:

let the 3 consecutive numbers be x,x+1,x+2

therefore x+x+1+x+2=90

=3x+3=90

=3x=87

x=87÷3

x=29

1st no.29

2nd 30

3rd 31