Math, asked by KingSrikar, 2 months ago

Hi There! It's Urgent. Please solve fastly
Question 1) Find Value of \rm{cos\:60^\circ\times cos\:30^\circ+sin\:60^\circ\times sin\:30^\circ=}
Question 2) Find Value of \rm{sin^2\:45^\circ+cos^2\:45^\circ+tan^2\:45^\circ}

Answers

Answered by ExploringMathematics
3

\rm{cos\:60^\circ\times cos\:30^\circ+sin\:60^\circ\times sin\:30^\circ=1/2\times\sqrt{3}/2+\sqrt{3}/2\times1/2}

\longrightarrow\rm{cos\:60^\circ\times cos\:30^\circ+sin\:60^\circ\times sin\:30^\circ=\sqrt{3}/4+\sqrt{3}/4}

\longrightarrow\rm{cos\:60^\circ\times cos\:30^\circ+sin\:60^\circ\times sin\:30^\circ=2(\sqrt{3}/4)}

\longrightarrow\rm{cos\:60^\circ\times cos\:30^\circ+sin\:60^\circ\times sin\:30^\circ=\sqrt{3}/2}

\rm{sin^2\:45^\circ+cos^2\:45^\circ+tan^2\:45^\circ=(1/\sqrt{2})^2+(1/\sqrt{2})^2+1^2 }

\longrightarrow\rm{sin^2\:45^\circ+cos^2\:45^\circ+tan^2\:45^\circ=1/2+1/2+1 }

\longrightarrow\rm{sin^2\:45^\circ+cos^2\:45^\circ+tan^2\:45^\circ=2/2+1 }

\longrightarrow\rm{sin^2\:45^\circ+cos^2\:45^\circ+tan^2\:45^\circ=1+1=2 }

Answered by ItzMissSanskari
18

Answer:

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