Question

hi there

please answer

Answer 1

$<b>$Given that, diameter(d) of cylinder is 1.4 m and length(h) is 8 m.
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)

= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20

Answer 2

Hey mate,

We know,

Diameter of cylinder = 1.4 m

Radius of cylinder = 1.4/2 = 0.7 m

So,

Height = 8m

Surface area of tank = 2 × pie × r × h + 2 × pie × r^2

plug in the values to get

= 41.36 m^2

Cost of 1m^2 = 20Rs

So cost of 41.36 m^2 = 41.36 × 20

= 827.2 Rs

hope this helps you out!

another example in the image!