Question

Hi there
pls ans this question fast its very important

Answer 1

The given numbers are in AP

a = 4

d = 3

Next two lines:

34 37 40 43 46

49 52 55 58 61 64

For the 20th line:

We can suppose it as, the number of terms in every line makes an AP, where:

a = 1

d = 1

an = a + (n - 1)d

a20 = 1 + 19

a20 = 20

Thus, it will contain 20 terms.

We will find the number of term which is the first term in the 20th line by first finding the sum of number of terms preceding the first term of 20th line.

Here, a = 1

n = 19

d = 1

sn = n/2(2a + (n-1)d)

s19 = 19/2(2+18)

s19 = 19/2(20)

s19 = 190

Thus, the first term of 20th line will be the 190th term of the AP with a = 4, d = 3

a190 = 4 + 189(3)

a190 = 571

Last term of the line will be 190 + 19 = 209 term of the AP with a = 4, d = 3

a209 = 4 + 209(3)

a209 = 631

Hope it helps!!