Question

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Answer 1

Answer:

466.66 bananas.

Step-by-step explanation:

Let the number of bananas in lot A and B be x and y, respectively

Two cases,

Case 1 :

Cost of the first lot at the rate of ₹ 5 for 3 bananas + Cost of the second lot at the rate of ₹ 2 per banana = Amount received

5x/3 + 2y = 800

5x + 6y = 2400       - (Eq. (i) )

Case 2 :

Cost of the first lot at the rate of ₹ 2 per banana + Cost of the second lot at the rate of ₹ 9 for 5 bananas = Amount received

2x + 9y/5 = 920

10x + 9y = 4600.      - (Eq. (ii) )

On multiplying in Eq. (i) by 2

and

then subtracting  with Eq. (ii)

we get

(10x + 12y) – (10x + 9y) = 4800 – 4600  

3y = 200

y = 200/3

Now, put the value of y in Eq. (i),

we get,

5x + 6 (200/3) = 2400  

=>  5x + 400 = 2400

=> x = 2000/5 = 400

Hence, Total number of bananas = Number of bananas in lot A + Number of bananas in lot B

= x + y = 400 + 200/3 = 466.66

Hence, he had 466.66 bananas.