Question

Hi there plz
prove that
2+2=5
by illegal method
★★NO SPAMMING at all★★
If u don't know then just ignore it
••••••••••••••••••••••••••••••••••••
Best answer will be marked as Brainlist

Answer 1

Heya!!!

←Here Is Your Answer→

→ Everyone Knows, 2+2=4

Now,

2+2=4

→2+2=4-9/2+9/2

→2+2=√(4-9/2)^2+9/2

→2+2={√16-2.4.9/2+(9/2)^}2+(9/2)

→2+2={√-20+(9/2)^2}+9/2

→2+2={√25-45+(9/2)^2}+(9/2)

→2+2={√(5)^2-2.9/2.5+(9/2)^2}+(9/2)

→2+2={√(5-9/2)^2}+(9/2)

→2+2={5-9/2+9/2}

→2+2=5 【Proved】

Hope My Answer Helped {:

Answer 2

$\bf HELLO \: \: DEAR,$

$\bf 2 + 2 = 4$

$\bf \: 4 - \frac{9}{2} + \frac{ 9}{2} \\ \\ \bf\sqrt{ {(4 - \frac{9}{2}) }^{2} } + \frac{9}{2} \\ \\ \bf \sqrt{16 + { (\frac{9}{2} )}^{2} - 2 \times 4 \times \frac{9}{2} } + \frac{9}{2} \\ \\ \bf \: \sqrt{16 + { (\frac{9}{2}) }^{2} - 36 } + \frac{9}{2} \\ \\ \bf \sqrt{ - 20 + { (\frac{9}{2})}^{2} } + \frac{9}{2} \\ \\ \bf \sqrt{25 - 45 + {( \frac{9}{2} )}^{2} } + \frac{9}{2} \\ \\ \bf \sqrt{ {5}^{2} - 2 \times 5 \times \frac{9}{2} + { (\frac{9}{2} )}^{2} } + \frac{9}{2} \\ \\ \bf \: \sqrt{ {(5 - \frac{9}{2} )}^{2} } + \frac{9}{2} \\ \\ \bf 5 - \frac{9}{2} + \frac{9}{2} \\ \\ \bf \: \: \: = 5$

$\bf hence, \: \: 2 + 2 = 5$

$\underline{\bf I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, \: \: THANKS}$