Question

Hi thr!!

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❌No spams ​

Answer 1

Sector angle, ß = 30°

Area of shaded region = ß/360 π (OD)² - ß/360 π (OC)² + ß/360 π (OB)² - ß/360 π (OA)²

= ( π/12 ) (196 - 110.25 + 49 - 12.25)

= (π/12) ( 122.5 )

= 11/6 × 17.5

= 32.08 cm²

Answer 2

Area of sector DO = pie r^2 × 30/360

= pie r^2/12

Now here r= DO= 4× 3.5 = 14

= pie ( 14)(14)/12

= 22/7 × 14 × 14 /12

= 44× 14/12 = 616/12 = 154/3 = 51.3



Area of sector CO

Here r= 3× 3.5 = 10.5

So area = pie × 10.5 × 10.5/12

= 28.84

Area of shaded DC = 51.3 - 28.84 = 22.46


Area of OB =

OB = 2× 3.5 = 7

= pie 7 × 7/ 12 = 22× 7/12 = 154/12 = 12.833


Area of OA

OA = 3.5

= pie .3.5 × 3.5/12 = 3.205

Area of AB = 12.833 -3.205 = 9.628


Total shaded area = 9.628 + 22.46 = 32.088