Math, asked by brownie62, 1 year ago

hi,
today's challenge !!
_______________
explain with full solution..
the best solution will be marked as brainlist!!

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Answers

Answered by siddhartharao77
5

Answer:

C

Step-by-step explanation:

Given: (A/3) = (B/4) = (C/5).

Let, (A/3) = (B/4) = (C/5) = k{Some constant}

Then:

(A/3) = K => A = 3K

(B/4) = k => B = 4k

(C/5) = k => C = 5k

Now,

A : B : C = 3K : 4K : 5K

             = 3 : 4 : 5


Hope it helps!

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brownie62: can u please give a pic
brownie62: tommorow is my exam
brownie62: please it's important sir
siddhartharao77: What pic
brownie62: photo of your solution in a notebook
siddhartharao77: Done
Answered by superjunior
4

annyeongHaseyo... :)

answer: option c

step-by-step explanation :

we know that a number will be 1 when both it's denominator and numerator are same as 2/2 = 1

if they all are equal so, it is easy to tell that they are either 0 or 1 as thier..

but according to this problem we can't take this rational number as 0.

so, answer is 3:4:5.

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