Question

hi
write the cube of
1.
$x + 2y \\ 2.a - \frac{1}{2}$

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Answer 1

Step-by-step explanation:

1. (x+2y)^3 = (x)^3 + (2y)^3+3(x)(2y)(x+2y)

= (x+2y)^3 = x^3 + 8y^3+6xy(x+2y)

= (x+2y)^3= x^3+ 8y^3 + 6x^2y +12xy^2

.......

2..(a-1/2)^3 = (a)^3 -(1/2)^3 -

3(a)^2(1/2)+3(a)(1/2)^2

= (a-1/2)^3 = a^3 -1/8 - 3a^2/2 +3a/4

.............. hope it's helpful

Answer 2

$hi \: mate \\ here \: is \: your \: answer \\ 1.( {x + 2y}) ^{3} \\ = {x}^{3} + {8y}^{3} + 6xy(x + 2y) \\ \\</p><p></p><p>2. ({a - \frac{1}{2} ) }^{3} \\ = {a}^{3} - \frac{1}{8} - \frac{3}{2}a(a - \frac{1}{2})$

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