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Prove that area of any quadrilateral is half the prodauct of its diagonals and sum of perpendiculars drawn to it from the opposite vertices i.e area (ABCD)=1/2 ×AC×(DP+BQ)
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ojasvikamrapaxuyi:
Sorry didnt see your question well. Instead of FG, use AG it is the same as it is the hight in the triangle. Similarly use HC instead of HE. Sorry for doing it a bit wrong.
Ok
No problem
Thnx
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