Question

higest 4 digit number divisible by 8,12,18,30

Answer 1

Answer:

In this case, the set of numbers is (12, 15, 18, 27). Their LCM will be divisible by all of these numbers from the set. Let’s find the LCM.

Steps to find the LCM:

The LCM is

12 = 3*4 = 2*2*3

(convert these numbers into prime factors)

15 = 3*5

18 = 2*3*3

27 = 3*3*3

LCM is found by multiplying the prime numbers with their maximum powers.

LCM = 3*3*3*2*2*5 (highest power of 3 is in 27, 2 in 12 and 5 in 15)

Hence LCM = 540

Now, the next part is easier.

The divisible numbers: 540*1, 540*2, .... , 540*n. (Where n is an integer.)

540*18 = 9720

540*19 = 10260 ( A FIVE DIGIT NUMBER)

Hence, the largest four-digit number divisible by 12, 15, 18, 27 is 9720.