Question

Highest marks obtained by a Student in her class is twice the lowest marks plus 9 the highest score is 91 what is the lowest score​

Answer 1

Step-by-step explanation:

Let the lowest score be x.

Step I: Highest marks obtained = 2x + 9

Step II: 2x + 9 = 91

is the required equation. Solving the equation, we have

2x + 9 = 91

⇒ 2x = 91 – 9 (Transposing 9 to RHS)

⇒ 2x = 82

⇒ x = 82/2

⇒ x = 41 is the required lowest marks.

Answer 2

Step-by-step explanation:

lets take the lowest score be x

Highest score=91

Twice the lowest score+9

=2x+9=91

=2x=91-9

2x=82

x=82/2

x=41

so, the lowest score is 41.

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