Question

hii after 10 days
Perpendicular distance from origin to the line 3x+4y−12=0 is​​

Answer 1

12/5 is correct answer 12/5

Answer 2

$\large{\underline{\sf{Solution-}}}$

We know that,

Perpendicular distance from a point (x,y) to the line ax + by + c = 0 is $\rm{\dfrac{ax + by +c}{\sqrt{a^2 + b^2}}}$

Here,

(x, y) = (0, 0)

ax + by +c = 3x + 4y - 12

So,

Perpendicular distance = $\rm{\dfrac{3(0) + 4(0) - 12}{\sqrt{3^2 + 4^2}}}$

=> $\rm{\dfrac{0 + 0 - 12}{\sqrt{9 + 16}}}$

=> $\rm{\dfrac{-12}{\sqrt{25}} = \dfrac{12}{5} units}$

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HOPES IT HELPS!:)