Question

hii answer this ....... ​

Answer 1

Answer:

BOD= AOC= 40 (opposite angle)

BOE= 70-AOC

BOE=70- 40= 30

AOB+BOE+EOC= 180 (liners pair)

70+EOC= 180

EOC= 180-70=110

BOC= BOE+EOC= 30 +110

BOC= 140

Answer 2

Given

✭ ∠AOC + ∠BOE = 70°

✭ ∠BOD = 40°

To Find

◈ Value of ∠BOE & ∠BOC?

Solution

Concept

Where we are gonna completely use the concept of linear pair, i.e Angle made by a straight line is equal to 180°

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From the figure we observe that,

➝ ∠AOC + ∠COE + ∠BOE = 180° «« Linear Pair »»

• ∠AOC + ∠BOE = 70°
• ∠COE = x°

Substituting the given values,

➝ 70°+x = 180°

➝ x = 180-70

➝ x = 110

We may also observe that,

➳ ∠COE + ∠BOE + ∠BOD = 180° «« Linear Pair »»

• ∠COE = 110°
• ∠BOD = 40°

So then on substituting the values,

➳ 110°+∠BOE+40° = 180°

➳ 150°+∠BOE = 180°

➳ ∠BOE = 180-150

➳ ∠BOE = 30°

Now ∠BOC will be,

➢ ∠BOC = ∠BOE+∠COE

• ∠BOE = 30°
• ∠COE = 110°

➢ ∠BOC = 30°+110°

➢ ∠BOC = 140°

∴ ∠BOE is 30° & ∠BOC is 140°

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