Math, asked by marcenary0912, 1 month ago

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Interesting Question Here !!

In Quadrilateral ABCD, diagonals AC and BD intersect at point E, such that
AE : EC = BE : ED
Show that :- ABCD is a Trapezium. Kindly,

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Answers

Answered by TheAestheticBoy
16

★ Question :-

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In Quadrilateral ABCD, diagonals AC and BD intersect at point E. Such that

AE : EC = BE : ED

Show that :- ABCD is a Trapezium.

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★ Answer :-

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ln the above attachment, ABCD is a quadrilateral with diagonals AC and BD intersect at point E .

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⟹ ln DEC and AEB

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⠀⠀⠀\sf  \small{ \frac{AE}{EC} = \frac{BE}{ED}} \:  \:  \: .... \:  \sf \small \pink{given} \\  \\  \sf \small{∠ \: DEC =∠ \: AEB } \:  \:  \: .... \:   \sf  \small \pink{vertically \: opposite\: angles} \\  \\  \sf \small{∴ \: EBA = \:  ∠  \: CDE} \:  \:  \: ....  \: \sf \small \pink{allternate \: angles} \\  \\  \sf \small{∴ \: AB  \: ∥ \:  DC} \\  \\  \boxed{ \sf{ \small{∴ \: Given  \: Fig \:  is  \: { \underline \red{Trapezium }}}}}

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\bigstar\:\small \green{ \fcolorbox{gray}{black} {\textbf{ Hence, Proved ✔ }}}

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