Question

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I need your help in this questions of 10th geometry

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Answer 1

Answer:

Question 1:

Find the distance between each of the following pairs of points.

(1) A(2, 3), B(4, 1)

(2) P(–5, 7), Q(–1, 3)

(3) R(0, –3), S(0, 52)

(4) L(5, –8), M(–7, –3)

(5) T(–3, 6), R(9, –10)

(6) W( –72 , 4), X(11, 4)

ANSWER:

(1) A(2, 3), B(4, 1)

AB=(2−4)2+(3−1)2−−−−−−−−−−−−−−−√=(−2)2+22−−−−−−−−−√=4+4−−−−√=22–√

(2) P(–5, 7), Q(–1, 3)

PQ=(−5−(−1))2+(7−3)2−−−−−−−−−−−−−−−−−−−√=(−4)2+42−−−−−−−−−√=16+16−−−−−−√=42–√

(3) R(0, –3), S(0, 52)

RS=(0−0)2+(−3−52)2−−−−−−−−−−−−−−−−−√=(−112)2−−−−−−√=1214−−−√=112

(4) L(5, –8), M(–7, –3)

LM=(5−(−7))2+(−8−(−3))2−−−−−−−−−−−−−−−−−−−−−−√=122+(−5)2−−−−−−−−−−√=144+25−−−−−−−√=169−−−√=13

(5) T(–3, 6), R(9, –10)

TR=(−3−9)2+(6−(−10))2−−−−−−−−−−−−−−−−−−−−√=(−12)2+(16)2−−−−−−−−−−−−√=144+256−−−−−−−−√=400−−−√=20

(6) W( –72 , 4), X(11, 4)

WX=(−72−11)2+(4−4)2−−−−−−−−−−−−−−−−−−√=(−292)2−−−−−−√=8414−−−√=292