Hii..Can anyone here solve this?
No spams please..i want a proper solution.
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aryan014:
omg itna llamba ques... mujhe bi ktne padenge yr :p
sry nishita mai bs comment kr rha hu... agr aata hota to pakka solve krta :(
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hey
here is our answer
=======
Total charge contained in volume R1 is
∫R104πr2dr*ρ0/r= 4πρ0∫R10rdr= 2πR12ρ0
total charge on the outer shell = surface area * surface charge density=−4πR22σ
if net charge is zero ,
4πR22σ = 2πR12ρ0or, R2R1=√ρ02σ
I hope this will help
#Prem
here is our answer
=======
Total charge contained in volume R1 is
∫R104πr2dr*ρ0/r= 4πρ0∫R10rdr= 2πR12ρ0
total charge on the outer shell = surface area * surface charge density=−4πR22σ
if net charge is zero ,
4πR22σ = 2πR12ρ0or, R2R1=√ρ02σ
I hope this will help
#Prem
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np cya
thank u so much @sharpyy
and thanks for brainlist
whats yr name
my pleasure^_^
yaa no thanks u deserved it
mmm prem
okay
nice talking to u ..thank u ..bbye
same here cya
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