Question

Hii doston!!


Prove that
$({a + b})^{2} = {a}^{2} + 2ab + {b}^{2}$
​

Answer 1

Hello dear!❤️

To prove:

$( {a + b})^{2} = {a}^{2} + 2ab + {b}^{2}$

L.H.S

$({a + b})^{2}$

$(a + b)(a + b)$

$a(a + b) + b(a + b)$

${a}^{2} + ab + ab + {b}^{2}$

${a}^{2} + 2ab + {b}^{2}$

L.H.S = R.H.S

${a}^{2} + 2ab + {b}^{2} = {a}^{2} + 2ab + {b}^{2}$

Proved ☺️

Hope this helps

@adiba31❤️

Answer 2

$\huge\mathfrak\blue{hello}$

╔═❤️══════════════╗

...HERE GØΣS UR ANS...

╚══════════════❤️═╝

Area of part 1 :

Part 1 is a square of length a.

Therefore area of part 1 = a2 ---------------------------- (i)

Area of part 2 :

Part 2 is a rectangle of length : b and width : a

Therefore area of part 2 = length * breadth = ba -------------------------(ii)

Area of part 3:

Part 3 is a rectangle of length: b and width : a

Therefore area of part 3 = length * breadth = ba --------------------------(iii)

Area of part 4:

Part 4 is a square of length : b

Therefore area of part 4 = b2 ----------------------------(iv)

So, Area of square of length (a+b) = (a+b)2 = (i) + (ii) + (iii) + (iv)

Therefore :

(a+b)2 = a2 + ba + ba +b2

i.e. (a+b)2 = a2 + 2ab + b2

Hence Proved.

 ❣❣HOPE IT HELPS U ❣❣

 ❣❣PLEASE MARK MY ANSWER AS BRAINLIEST ❣❣

FOLLOW ME

 ❣❣THANKS ❣❣

☺☺☺

#BEBRAINLY

$\huge\mathfrak{Follow \ Me}$