Question

Hii everyone ❣️

given are three numbers.

if the second and the third numbers

respectively at 25% and 50% more than

the first then what percent of the

second is the third?​

Answer 1

Answer:

solution:

Let third number is X.

Then first no = 20% of X = 20X/100

Second number = 50% of X = 50X/100

Percent of first no of second no,

= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%.

Answer 2

$\huge\tt\underline{\red{A}{\blue{N}{\green{S}{\purple{W}{\pink{E}{\red{R}}}}}}}$

$let \: the \: first \: no. \: be \: = \: x \\ \\ second \: no. \: = \: \frac{25}{100} \times x \\ \\ third \: no. = \: \frac{50}{100} \times x \\ \\ first \: no. \: be \: = \: ( \frac{25}{100} \times x)( \frac{50}{100} \times x) \times 100 \: = \: 20\%$