hii everyone im feeling so sad i have forget how to solve this type of math
plzz solution
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Here is your answer buddy,
When ever you find number with huge distinct powers it is always suggested to bring it under a single power and comparing the basses rather than bringing it to single base.
Take the powers of the numbers 60,48,36,24
GCD of 60,48,36,24 is 12. Now separate the power 12 and compare the numbers i.e.,
2^60 = (2^5)^12 = 32^12 (Since, 60 = 12*5 and a^(b*c)=(a^b)^c)
3^48 = (3^4)^12 = 81^12
4^36 = (4^3)^12 = 64^12
5^24 = (5^2)^12 = 25^12
Now all the powers are same and we can compare the bases and we can arrange them in ascending order as follows
5^24 < 2^60 < 4^36 < 3^48
This approach helps in comparing any number of bases with large powers.
HOPE THIS HELPS YOU. PLEASE MARK ME AS BRAINLIEST!!!!
When ever you find number with huge distinct powers it is always suggested to bring it under a single power and comparing the basses rather than bringing it to single base.
Take the powers of the numbers 60,48,36,24
GCD of 60,48,36,24 is 12. Now separate the power 12 and compare the numbers i.e.,
2^60 = (2^5)^12 = 32^12 (Since, 60 = 12*5 and a^(b*c)=(a^b)^c)
3^48 = (3^4)^12 = 81^12
4^36 = (4^3)^12 = 64^12
5^24 = (5^2)^12 = 25^12
Now all the powers are same and we can compare the bases and we can arrange them in ascending order as follows
5^24 < 2^60 < 4^36 < 3^48
This approach helps in comparing any number of bases with large powers.
HOPE THIS HELPS YOU. PLEASE MARK ME AS BRAINLIEST!!!!
taniya55555:
good
Answered by
1
the powers of the numbers are 60,48,36,24
LCM of 60, 48, 36, 24 is 12. Now separate the power 12 and compare the numbers i.e.,
2^60 = (2^5)^12 = 32^12 (Since, 60 = 12*5 and a^(b*c)=(a^b)^c)
3^48 = (3^4)^12 = 81^12
4^36 = (4^3)^12 = 64^12
5^24 = (5^2)^12 = 25^12
Now all the powers are same and we can compare the bases and we can arrange them in ascending order :
5^24 < 2^60 < 4^36 < 3^48
LCM of 60, 48, 36, 24 is 12. Now separate the power 12 and compare the numbers i.e.,
2^60 = (2^5)^12 = 32^12 (Since, 60 = 12*5 and a^(b*c)=(a^b)^c)
3^48 = (3^4)^12 = 81^12
4^36 = (4^3)^12 = 64^12
5^24 = (5^2)^12 = 25^12
Now all the powers are same and we can compare the bases and we can arrange them in ascending order :
5^24 < 2^60 < 4^36 < 3^48
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