Question

hii friends do this question in different or simple methods u have don't need solutions but giving just methods
question no. 3rd and 4th
refer to pic
class 9th cbse

pic is cleared OK
only u know then answer

Answer 1

Heyy

It's Sneha

Here is ur answer of question 4

U just need to prove SAS rule it is simplest method to solve this question

Hope it helps

#Deep

Answer 2

heya it's Aastha....

4.
Given that ABCD is a square.

To prove : AC = BD and AC and BD bisect each other at right angles.

Proof: 

(i)  In a Δ ABC and Δ BAD,

AB =  AB ( common line)

BC = AD ( opppsite sides of a square)

∠ABC = ∠BAD ( = 90° )

Δ ABC ≅ Δ BAD ( By SAS property)

AC = BD ( by CPCT).

(ii) In a Δ OAD and Δ OCB,

AD = CB ( opposite sides of a square)

∠OAD = ∠OCB ( transversal AC )

∠ODA = ∠OBC ( transversal BD )

ΔOAD ≅ ΔOCB (ASA property)

OA = OC  ---------(i)

Similarly OB = OD ----------(ii)

From (i) and (ii)  AC and BD bisect each other.

Now in a ΔOBA and ΔODA,

OB = OD ( from (ii) )

BA = DA

OA = OA  ( common line )

ΔAOB = ΔAOD ----(iii) ( by CPCT

∠AOB + ∠AOD = 180°   (linear pair)

2∠AOB  = 180°

∠AOB = ∠AOD = 90°

∴AC and BD bisect each other at right angles.