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Q-1)If tan 2A-CotA-18°).Then the value of A
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Answered by
2
Answer:
Given tan2A=cot(A−18
0
)
⇒cot(90−2A)=cot(A−18
0
)[∵tanθ=cot(90−θ)]
Comparing angles we get
90−2A=A−18
⇒90+18=A+2A
⇒3A=108
⇒A=
3
108
⇒A=36
∘
Answered by
1
If tan 2A = cot (A - 18°), where 2A is an acute angle, then the value of A is 36°.
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