Hii Friends , I am here with the topic : Logarithms - Write 4log4+2log5-log15 as single algorithm. Please help me friends i need it !!
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6
4log4+2log5-log15
=log4^4+log5^2- log15
=log256+25-log15
=log (256×25/15)
=426.67
=log4^4+log5^2- log15
=log256+25-log15
=log (256×25/15)
=426.67
krishiganesh:
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Answered by
4
Hey there!
4 log 4 + 2 log 5 - log 15
= log 4^4 + log 5 ^ 2 - log 15
= log ( 4 ^ 4 * 5 ^ 2 ) - log 15
![= log( \frac{ {4}^{4} \times {5}^{2} }{15} ) \\ \\ = log( \frac{256 \times 5}{3} ) \\ \\ = log( \frac{1280}{3} ) = log( \frac{ {4}^{4} \times {5}^{2} }{15} ) \\ \\ = log( \frac{256 \times 5}{3} ) \\ \\ = log( \frac{1280}{3} )](https://tex.z-dn.net/?f=+%3D++log%28++%5Cfrac%7B+%7B4%7D%5E%7B4%7D+%5Ctimes++%7B5%7D%5E%7B2%7D++%7D%7B15%7D+++%29++%5C%5C++%5C%5C++%3D++log%28+%5Cfrac%7B256+%5Ctimes+5%7D%7B3%7D+%29++%5C%5C++%5C%5C++%3D++log%28+%5Cfrac%7B1280%7D%7B3%7D+%29+)
Hope helped!
4 log 4 + 2 log 5 - log 15
= log 4^4 + log 5 ^ 2 - log 15
= log ( 4 ^ 4 * 5 ^ 2 ) - log 15
Hope helped!
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