Question

Hii friends.
Please answer me this question.

I will mark u as brainliest. please.

Answer 1

In parallelogram ABCD and rectangle ABEF

AB=FE (opposite sides of llgm and res are equal)

& AB=CD(opposite sides of llgm and res are equal)

As in ∆AFC <F=90 and AC is hypotonus

Therefore, AF<AC

As AF=BE

AC=BD

=> AF< AC (i)

BE <BD (ii)

PERIMETER OF llgm ABCD= AB+BC+CD+DA (iii)

PERIMETER OF rectangle ABEF= AB+BE+EF+AF (iv)

FROM (i), (ii) ,(iii)& (iv) we get

AB+BC+CD+DA> AB+BE+EF+AF

=> PERIMETER OF llgm > PERIMETER OF rectangle ABEF