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Since we do not know that whether the plate and body move together or not, we make assumptions as follows:
Treating both the blocks as a system moving with acceleration
we get,

To check the validity of our assumption let us calculate the frictional force
. Consider the plate,

Since, the static friction does not exceed
, our assumption is incorrect.
This means that the body is sliding relative to the plate and therefore kinetic friction is present.
Now, consider the plate again,
Treating both the blocks as a system moving with acceleration
To check the validity of our assumption let us calculate the frictional force
Since, the static friction does not exceed
This means that the body is sliding relative to the plate and therefore kinetic friction is present.
Now, consider the plate again,
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riddhimishra123:
thanks dear
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