Question

hii friends plzz solve Questions no. 4 and 6th also

Answer 1

Hi Tanya,

Q4 is easy just little tricky.

i. Greatest side = Side opposite to highest angle
ans. AR

ii. Two side are equal if their corresponding angles are equal.
ans. Here In triangle(ASR)...180-(120+30)=30. so both <SRA = <SAR = 30
so two equal sides are SR and SA.

iii. smallest side of triangle is the side opposite to smallest angle.
ans. SQ. since <SAQ = 180-(90+50) = 40.

Q6
This is to be solved using the fact that side opposite to greater angle is more in length.

here since x>y
180-x < 180-y
so sides opposite to 180-y is greater than side opposite to 180-x as x>y.
therefore AB > AC

Hope it helped
Let me know if you have any further doubt.
Cheers !!!

Answer 2

Angle X>y
Therefore side opposite to it
I.e., an and ac
So Ab>Ac