Question

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The diameter of a roller is 84 cm and its length is 120 cm.It takes 500 complete revolutions to move once to level a playground.Find the area of the playground in m^2.


This answer is 1584 m^2

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####Brainlygodess####

Answer 1

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Given,

Diameter = d = 84cm

Radius = r = d/2 = 42cm

Length = l = 120 cm

T.S.A of cylinder = 2πrh
                           = 2 x 22/7 x 42 x 120
                           = 31680 cm²

Area levelled by 500 revolution = Area of playground

= 500 x 31680cm²

= 15840000 cm² [ change into m]

= 1584 m²

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Answer 2

Heya !

Here's your answer !!


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GIVEN THAT :

Diameter of a roller = 84 cm

Lenght ( h ) = 120 cm

It takes 500 revolutions to move once over to level a playground.



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TO FIND

Area of the playground in m^2



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SOLUTION


Radius of the roller = 84/2 = 42 cm

Here, we'll find the Curved Surface Area ( C.S.A. ) of the roller

C.S.A. = 2 × 22/7 × r × h

=> 2 × 22/7 × 42 × 120

=> 240 × 22 × 6

=> 31680 cm^2


Area of Playground =

=> C.S.A. × 500

=> 31680 × 500

=> 15840000 cm^2

We know,

1 m = 100 cm

Therefore,

1 m^2 = 10000 cm^2

Converting cm^2 into m^2



=> 15840000/10000

=> 1584 m^2



Ans ) The area of the playground is 1584 m^2



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Thanks !!