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The diameter of a roller is 84 cm and its length is 120 cm.It takes 500 complete revolutions to move once to level a playground.Find the area of the playground in m^2.
This answer is 1584 m^2
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####Brainlygodess####
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Answered by
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☺️☺️☺️Hey mate ☺️☺️
d = 84 cm
so r =84/2= 42 cm
and length = h = 120 cm
1 revolution = curved surface area of cylinder
= 2 pie r h
= 2 × 22/7 × 42 × 120
= 44× 6× 120
=31680cm2
= 31680÷10000
=3.168 m2
so 500 revolution = 500× 3.168
= 1584 m2
Hence the area of playground = 1584 m2
d = 84 cm
so r =84/2= 42 cm
and length = h = 120 cm
1 revolution = curved surface area of cylinder
= 2 pie r h
= 2 × 22/7 × 42 × 120
= 44× 6× 120
=31680cm2
= 31680÷10000
=3.168 m2
so 500 revolution = 500× 3.168
= 1584 m2
Hence the area of playground = 1584 m2
Answered by
0
Given,
Diameter of Roller = 84 cm = 84/100 m = 0.84m
Radius of Roller = 0.84/2 m = 0.42 m
Height of Roller = 120 cm = 120/100 m = 1.20 m
Since, The Roller is in the form of Cylinder.
Area of Roller covered in 500 Revolutions = Area of Playground.
=> Area = (500 x 2 x 22/7 x 0.42 x 1.20) m^2
=> Area = 1584 m^2
Hence, Area of Playground = 1584 m^2
Be Brainly
Diameter of Roller = 84 cm = 84/100 m = 0.84m
Radius of Roller = 0.84/2 m = 0.42 m
Height of Roller = 120 cm = 120/100 m = 1.20 m
Since, The Roller is in the form of Cylinder.
Area of Roller covered in 500 Revolutions = Area of Playground.
=> Area = (500 x 2 x 22/7 x 0.42 x 1.20) m^2
=> Area = 1584 m^2
Hence, Area of Playground = 1584 m^2
Be Brainly
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