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The diameter of a roller is 84 cm and its length is 120 cm.It takes 500 complete revolutions to move once to level a playground.Find the area of the playground in m^2.
This answer is 1584 m^2
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####Brainlygodess####
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Answered by
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Given,
Diameter = d = 84cm
Radius = r = d/2 = 42cm
Length = l = 120 cm
T.S.A of cylinder = 2πrh
= 2 x 22/7 x 42 x 120
= 31680 cm²
Area levelled by 500 revolution = Area of playground
= 500 x 31680cm²
= 15840000 cm² [ change into m]
= 1584 m²
Answered by
2
Given,
Diameter of Roller = 84 cm = 84/100 m = 0.84m
Radius of Roller = 0.84/2 m = 0.42 m
Height of Roller = 120 cm = 120/100 m = 1.20 m
Since, The Roller is in the form of Cylinder.
Area of Roller covered in 500 Revolutions = Area of Playground.
=> Area = (500 x 2 x 22/7 x 0.42 x 1.20) m^2
=> Area = 1584 m^2
Hence, Area of Playground = 1584 m^2
Be Brainly
Diameter of Roller = 84 cm = 84/100 m = 0.84m
Radius of Roller = 0.84/2 m = 0.42 m
Height of Roller = 120 cm = 120/100 m = 1.20 m
Since, The Roller is in the form of Cylinder.
Area of Roller covered in 500 Revolutions = Area of Playground.
=> Area = (500 x 2 x 22/7 x 0.42 x 1.20) m^2
=> Area = 1584 m^2
Hence, Area of Playground = 1584 m^2
Be Brainly
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