hii frnds....
answer me this question....
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Find the zeroes
vii ) x = -b / a
viii) x = -4
ix ) x = -a
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Answer:
(vii) x = -b/a
(viii) x = 0
(ix) x = 0
Step-by-step explanation:
Given,
(vii) p(x) = ax + b
Then,
ax + b = 0
=> ax = -b
=> x = -b/a
Hence, x = -b/a
(viii) q(x) = 4x
=> 4x = 0
=> x = 0/4 = 0
Hence, x = 0
(ix) p(x) = ax
=> ax = 0
=> x = 0/a = 0
Hence, x = 0
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