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prove by longest method possible ..please faster
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From 3x = 2x + x
Applying tan on both sides..
tan3x = tan (2x+x)
tan3x = (tan2x+tanx)/1-tan2x tanx
(1-tan2x tanx)tan3x = tan2x+tanx
tan3x - tanx tan2x tan3x = tan2x+tanx
tanx tan2x tan3x = tan3x-tan2x-tanx
Hence it is proved.
Hope this helps you.
Applying tan on both sides..
tan3x = tan (2x+x)
tan3x = (tan2x+tanx)/1-tan2x tanx
(1-tan2x tanx)tan3x = tan2x+tanx
tan3x - tanx tan2x tan3x = tan2x+tanx
tanx tan2x tan3x = tan3x-tan2x-tanx
Hence it is proved.
Hope this helps you.
Anonymous:
yes i am preparing for jee
so i think in many ways
which will suite u
higher geometry
or higher trigonometry
ok
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you can see your answer and
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