hii good evening I wanna ask question please give fast I am wating diagram is give in it .
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In ∆ AOD and ∆ BOC, we have
<OAD = <BOC (each 90°)
AD = BC (given)
OD = OC
∆AOD ≈ ∆BOC (R.H.S criteria)
AO = BO (c.p.c.t.)
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hey sis! can you tell me in which of your friends did he sended it
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