Math, asked by Sanskriti141, 1 year ago

Hii Good Morning everyone!!

Solve the following given in the attachment.
Plz show process also...

Attachments:

gayatrichauhanp9mj8k: under root 5
Sanskriti141: how dear
gayatrichauhanp9mj8k: square p-1/p
gayatrichauhanp9mj8k: and p+1/p
gayatrichauhanp9mj8k: u will get value of p^2+^1/p
gayatrichauhanp9mj8k: sanskriti can attacth some attachment
gayatrichauhanp9mj8k: PROFILE QUES

Answers

Answered by RanjanKumar14
26
Hi !! there !!!


given ,


p + 1/ p = 3


squaring both side we get


p²+ 1/ p² + 2 = 9


p² + 1/ p² = 7 ----------------------------(1)


now ,


p - 1/ p = ??


squaring both side


( p - 1 / p )²= p² + 1/ p² - 2




p² + 1 / p² = 7.
from equation 1



( p - 1 / p)²= 7 - 2


p -1/ p = ±√5


hope it helps !!







Sanskriti141: Thanks a lot
gayatrichauhanp9mj8k: u r welcome
Sanskriti141: not to u dear
gayatrichauhanp9mj8k: ok
kingji: why we plus 2in i eq
Sanskriti141: because it is the formula for (a+b)^2
kingji: ok thanks
Sanskriti141: welcome
kingji: and why we -2
Answered by Soumyadwip
2
The answer is attached herewith.
Contact me for any further difficulties or explanations.
Attachments:
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